2024-2025 北美秋招 OA 真题汇总csvosupport* 整理最新题目，助你高效备战秋招
📋 高频题目
1. 数组中的K 大元
import heapq
def findKthLargest(nums, k):
return heapq.nlargest(k, nums)[-1]
# 或使用快速选择
def findKthLargest_quickselect(nums, k):
def partition(left, right):
pivot = nums[right]
i = left
for j in range(left, right):
if nums[j] >= pivot:
nums[i], nums[j] = nums[j], nums[i]
i += 1
nums[i], nums[right] = nums[right], nums[i]
return i
left, right = 0, len(nums) - 1
k_index = k - 1
while left <= right:
pivot_index = partition(left, right)
if pivot_index == k_index:
return nums[pivot_index]
elif pivot_index < k_index:
left = pivot_index + 1
else:
right = pivot_index - 1
2. 最长公共子序列
def longestCommonSubsequence(text1, text2):
m, n = len(text1), len(text2)
dp = [[0] * (n + 1) for _ in range(m + 1)]
for i in range(1, m + 1):
for j in range(1, n + 1):
if text1[i-1] == text2[j-1]:
dp[i][j] = dp[i-1][j-1] + 1
else:
dp[i][j] = max(dp[i-1][j], dp[i][j-1])
return dp[m][n]
3. 接雨
def trap(height):
if not height:
return 0
left, right = 0, len(height) - 1
left_max, right_max = 0, 0
water = 0
while left < right:
if height[left] < height[right]:
if height[left] >= left_max:
left_max = height[left]
else:
water += left_max - height[left]
left += 1
else:
if height[right] >= right_max:
right_max = height[right]
else:
water += right_max - height[right]
right -= 1
return water
💼 csvosupport 助力
*题库汇 - 2024-2025 最新题 公司分类 - 按公司整理真 难度分级 - Easy/Medium/Hard 时间管理 - OA 答题策略
联系 csvosupport，专业秋OA 辅助
*标签 #秋招 #北美 #CodeTest #OA #2024 #2025 #OA代做 #面试辅助 #一亩三分地
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